Difference between revisions of "Exclusive disjunction"

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==See also==
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==Syllabus==
  
 
===Logical operators===
 
===Logical operators===
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* [[Ampheck]]
 
* [[Ampheck]]
* [[Boolean algebra]]
 
 
* [[Boolean domain]]
 
* [[Boolean domain]]
 
* [[Boolean function]]
 
* [[Boolean function]]
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* [[Boolean-valued function]]
 
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* [[Boolean logic]]
 
* [[Laws of Form]]
 
* [[Logic gate]]
 
 
* [[Logical graph]]
 
* [[Logical graph]]
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* [[Logical matrix]]
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* [[Minimal negation operator]]
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* [[Peirce's law]]
 
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* [[Peirce's law]]
 
 
* [[Propositional calculus]]
 
* [[Propositional calculus]]
* [[Sole sufficient operator]]
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* [[Truth table]]
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* [[Universe of discourse]]
 
* [[Zeroth order logic]]
 
* [[Zeroth order logic]]
 
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==Document history==
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Portions of the above article were adapted from the following sources under the [[GNU Free Documentation License]], under other applicable licenses, or by permission of the copyright holders.
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* [http://mywikibiz.com/Exclusive_disjunction Exclusive Disjunction], [http://mywikibiz.com/ MyWikiBiz]
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* [http://beta.wikiversity.org/wiki/Exclusive_disjunction Exclusive Disjunction], [http://beta.wikiversity.org/ Beta Wikiversity]
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* [http://www.getwiki.net/-Exclusive_disjunction Exclusive Disjunction], [http://www.getwiki.net/ GetWiki]
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* [http://www.wikinfo.org/index.php/Exclusive_disjunction Exclusive Disjunction], [http://www.wikinfo.org/ Wikinfo]
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* [http://www.textop.org/wiki/index.php?title=Exclusive_disjunction Exclusive Disjunction], [http://www.textop.org/wiki/ Textop Wiki]
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* [http://en.wikipedia.org/w/index.php?title=Exclusive_disjunction Exclusive Disjunction], [http://en.wikipedia.org/ Wikipedia]
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[[Category:Philosophy]]
 
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[[Category:Semiotics]]
 
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Revision as of 01:18, 6 April 2010

Exclusive disjunction, also known as logical inequality or symmetric difference, is an operation on two logical values, typically the values of two propositions, that produces a value of true just in case exactly one of its operands is true.

The truth table of p XOR q (also written as p + q or p ≠ q) is as follows:


Exclusive Disjunction
p q p XOR q
F F F
F T T
T F T
T T F


The following equivalents can then be deduced:

\[\begin{matrix} p + q & = & (p \land \lnot q) & \lor & (\lnot p \land q) \\ \\ & = & (p \lor q) & \land & (\lnot p \lor \lnot q) \\ \\ & = & (p \lor q) & \land & \lnot (p \land q) \end{matrix}\]

Syllabus

Logical operators

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Related topics

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Document history

Portions of the above article were adapted from the following sources under the GNU Free Documentation License, under other applicable licenses, or by permission of the copyright holders.

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